(2w^2-2)/(w^2-4w-5)

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Solution for (2w^2-2)/(w^2-4w-5) equation: 


D( w )

w^2-(4*w)-5 = 0

w^2-(4*w)-5 = 0

w^2-(4*w)-5 = 0

w^2-4*w-5 = 0

w^2-4*w-5 = 0

DELTA = (-4)^2-(-5*1*4)

DELTA = 36

DELTA > 0

w = (36^(1/2)+4)/(1*2) or w = (4-36^(1/2))/(1*2)

w = 5 or w = -1

w in (-oo:-1) U (-1:5) U (5:+oo)

(2*w^2-2)/(w^2-(4*w)-5) = 0

(2*w^2-2)/(w^2-4*w-5) = 0

w^2-4*w-5 = 0

w^2-4*w-5 = 0

DELTA = (-4)^2-(-5*1*4)

DELTA = 36

DELTA > 0

w = (36^(1/2)+4)/(1*2) or w = (4-36^(1/2))/(1*2)

w = 5 or w = -1

(w+1)*(w-5) = 0

(2*w^2-2)/((w+1)*(w-5)) = 0

2*w^2 = 2 // : 2

w^2 = 1

w^2 = 1 // ^ 1/2

abs(w) = 1

w = 1 or w = -1

w in { -1} 

w = 1

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